a) \(\left(\frac{11}{12}:\frac{44}{16}\right)\cdot\left(-\frac{1}{3}+\frac{1}{2}\right)=\left(\frac{11}{12}\cdot\frac{16}{44}\right)\cdot\frac{1}{6}=\left(\frac{1}{3}\cdot\frac{4}{4}\right)\cdot\frac{1}{6}=\frac{1}{3}\cdot\frac{1}{6}=\frac{1}{18}\)

b) \(\frac{\left(-5\right)^2\cdot\left(-5\right)^3\cdot16}{5^4\cdot\left(-2\right)^4}=\frac{5^2\cdot\left(-5\right)^3\cdot2^4}{5^4\cdot2^4}=\frac{5^2\cdot\left(-5\right)^3\cdot2^4}{5^2\cdot5^2\cdot2^4}=\frac{\left(-5\right)^3}{5^2}=-5\)

c) \(7,5:\left(-\frac{5}{3}\right)+2\frac{1}{2}:\left(-\frac{5}{3}\right)=7,5:\left(-\frac{5}{3}\right)+2,5:\left(-\frac{5}{3}\right)=\left(7,5+2,5\right):\left(-\frac{5}{3}\right)\)

\(=10:\left(-\frac{5}{3}\right)=10\cdot\left(-\frac{3}{5}\right)=-6\)

d) \(\left|-\frac{3}{7}\right|:\left(-3\right)^2-\sqrt{\frac{4}{49}}=\frac{3}{7}:9-\frac{2}{7}=\frac{3}{7}\cdot\frac{1}{9}-\frac{2}{7}=\frac{1}{7}\cdot\frac{1}{3}-\frac{2}{7}=\frac{1}{21}-\frac{2}{7}=-\frac{5}{21}\)

Mk ko biết lm nhưng cứ k thoải mái nha

SORRY

\(\frac{\left(\frac{2}{3}\right)^3\cdot\left(-\frac{3}{4}^2\right)\cdot\left(-1\right)^{2003}}{\left(\frac{2}{5}\right)^2\cdot\left(-\frac{5}{12}\right)^3}\)

\(=\frac{\frac{8}{27}\cdot\frac{9}{16}\cdot\left(-1\right)}{\frac{4}{25}\cdot\left(-\frac{125}{1728}\right)}\)

\(=\frac{-\frac{1}{6}}{-\frac{5}{432}}=-\frac{1}{6}:\left(-\frac{5}{432}\right)=\frac{72}{5}\)

\(\left[6.\left(\frac{-1}{3}\right)^2-3.\left(\frac{-1}{3}\right)+1\right]:\left(\frac{-1}{3}-1\right)\)

\(=\left[6.\frac{1}{9}-\left(-1\right)+1\right]:\frac{-4}{3}\)

\(=\left[\frac{2}{3}-\left(-1\right)+1\right]:\frac{-4}{3}\)

\(=\frac{8}{3}:\frac{-4}{3}=\frac{-24}{12}=-2\)

~ Hok tốt ~

\(\left[6\cdot\left(-\frac{1}{3}\right)^2-3\cdot\left(-\frac{1}{3}\right)+1\right]:\left(-\frac{1}{3}-1\right)\)

\(=\left[6\cdot\left(-\frac{1}{9}\right)+1+1\right]:\left(-\frac{4}{3}\right)\)

\(=\left(-\frac{2}{3}+2\right):\left(-\frac{4}{3}\right)\)

\(=\frac{4}{3}:\left(-\frac{4}{3}\right)=-1\)

a, Tự chép đề bài ((:

\(=\frac{1}{9}\cdot1+\left(-\frac{1}{243}\right)\cdot\frac{9}{2}\)

\(=\frac{1}{9}-\frac{1}{54}\)

\(=\frac{5}{54}\)

b, 1. \(\left(\frac{2^2\cdot2^3}{4^2\cdot16}\right)^{15}\)

\(=\left(\frac{2^5}{2^4\cdot2^4}\right)^5=\left(\frac{2^5}{2^8}\right)^5=\left(\frac{1}{2^3}\right)^5=\left(\frac{1}{8}\right)^5=\frac{1}{8^5}\)(Để vậy đi :v)

     2. \(\left(\frac{2^6}{16^2}\right)^{10}\)

\(=\left(\frac{2^6}{2^8}\right)^{10}=\left(\frac{1}{2^2}\right)^{10}=\frac{1}{2^{20}}\)

c, \(\frac{2^{15}\cdot9^4}{6^6\cdot8^3}\)

\(=\frac{2^{15}\cdot\left(3^2\right)^4}{\left(2\cdot3\right)^6\cdot\left(2^3\right)^3}=\frac{2^{15}\cdot3^8}{2^6\cdot3^6\cdot2^9}=\frac{2^{15}\cdot3^8}{2^{15}\cdot3^6}=\frac{3^2}{1}=3^2=9\)

KQ:\(\frac{1}{5}\)

cho tớ xin cách lm

bạn ấn vao đúng 0 sẽ có câu trả lời

giúp mình với các bạn ơi

Bài 1:

a) Ta có: \(\frac{5}{6}-\frac{2}{3}+\frac{1}{4}\)

\(=\frac{10}{12}-\frac{8}{12}+\frac{3}{12}\)

\(=\frac{2+3}{12}=\frac{5}{12}\)

b) Ta có: \(1\frac{11}{12}-\frac{5}{12}\cdot\left(\frac{4}{5}-\frac{1}{10}\right):\frac{-5}{12}\)

\(=\frac{23}{12}-\frac{5}{12}\cdot\left(\frac{8}{10}-\frac{1}{10}\right)\cdot\frac{-12}{5}\)

\(=\frac{23}{12}-\frac{5}{12}\cdot\frac{7}{10}\cdot\frac{-12}{5}\)

\(=\frac{23}{12}-\frac{-7}{10}\)

\(=\frac{115}{60}+\frac{42}{60}=\frac{157}{60}\)

Bài 2:

a) Ta có: \(\frac{1}{2}\cdot x-\frac{2}{5}=\frac{1}{5}\)

\(\Leftrightarrow\frac{1}{2}\cdot x=\frac{1}{5}+\frac{2}{5}=\frac{3}{5}\)

\(\Leftrightarrow x=\frac{3}{5}:\frac{1}{2}=\frac{3}{5}\cdot2=\frac{6}{5}\)

Vậy: \(x=\frac{6}{5}\)

b) Ta có: \(\left(1-2x\right)\cdot\frac{4}{3}=\left(-2\right)^3\)

\(\Leftrightarrow\left(1-2x\right)\cdot\frac{4}{3}=-8\)

\(\Leftrightarrow1-2x=-8:\frac{4}{3}=-8\cdot\frac{3}{4}=-6\)

\(\Leftrightarrow-2x=-6-1=-7\)

hay \(x=\frac{7}{2}\)

Vậy: \(x=\frac{7}{2}\)

Bài 1:

a) Ta có: 

b) Ta có: 

Bài 2:

a) Ta có: 

Vậy: 

b) Ta có: 

hay 

Vậy: